Skip to content
Snippets Groups Projects
Commit efd164b5 authored by Jeffrey Hugo's avatar Jeffrey Hugo Committed by Stephen Boyd
Browse files

clk: qcom: Allow constant ratio freq tables for rcg


Some RCGs (the gfx_3d_src_clk in msm8998 for example) are basically just
some constant ratio from the input across the entire frequency range.  It
would be great if we could specify the frequency table as a single entry
constant ratio instead of a long list, ie:

	{ .src = P_GPUPLL0_OUT_EVEN, .pre_div = 3 },
        { }

So, lets support that.

We need to fix a corner case in qcom_find_freq() where if the freq table
is non-null, but has no frequencies, we end up returning an "entry" before
the table array, which is bad.  Then, we need ignore the freq from the
table, and instead base everything on the requested freq.

Suggested-by: default avatarStephen Boyd <sboyd@kernel.org>
Signed-off-by: default avatarJeffrey Hugo <jeffrey.l.hugo@gmail.com>
Link: https://lkml.kernel.org/r/20191031185715.15504-1-jeffrey.l.hugo@gmail.com


Signed-off-by: default avatarStephen Boyd <sboyd@kernel.org>
parent ba1d366d
No related branches found
No related tags found
No related merge requests found
...@@ -220,6 +220,8 @@ static int _freq_tbl_determine_rate(struct clk_hw *hw, const struct freq_tbl *f, ...@@ -220,6 +220,8 @@ static int _freq_tbl_determine_rate(struct clk_hw *hw, const struct freq_tbl *f,
if (clk_flags & CLK_SET_RATE_PARENT) { if (clk_flags & CLK_SET_RATE_PARENT) {
rate = f->freq; rate = f->freq;
if (f->pre_div) { if (f->pre_div) {
if (!rate)
rate = req->rate;
rate /= 2; rate /= 2;
rate *= f->pre_div + 1; rate *= f->pre_div + 1;
} }
......
...@@ -29,6 +29,9 @@ struct freq_tbl *qcom_find_freq(const struct freq_tbl *f, unsigned long rate) ...@@ -29,6 +29,9 @@ struct freq_tbl *qcom_find_freq(const struct freq_tbl *f, unsigned long rate)
if (!f) if (!f)
return NULL; return NULL;
if (!f->freq)
return f;
for (; f->freq; f++) for (; f->freq; f++)
if (rate <= f->freq) if (rate <= f->freq)
return f; return f;
......
0% Loading or .
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment